0.0001x^2+0.02x-2.5=0

Solution for 0.0001x^2+0.02x-2.5=0 equation:

0.0001x^2+0.02x-2.5=0

a = 0.0001; b = 0.02; c = -2.5;
Δ = b2-4ac
Δ = 0.022-4·0.0001·(-2.5)
Δ = 0.0014
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.02)-\sqrt{0.0014}}{2*0.0001}=\frac{-0.02-\sqrt{0.0014}}{0.0002}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.02)+\sqrt{0.0014}}{2*0.0001}=\frac{-0.02+\sqrt{0.0014}}{0.0002}
$